学習環境
- Surface 3 (4G LTE)、Surface 3 タイプ カバー、Surface ペン(端末)
- Windows 10 Pro (OS)
- Nebo(Windows アプリ)
- iPad Pro + Apple Pencil
- MyScript Nebo(iPad アプリ)
- 参考書籍
代数系入門 (松坂 和夫(著)、岩波書店)の第1章(整数)、6(同値関係、合同式)、問題5.を取り組んでみる。
d を m の任意の約数とすれば、ある整数 k が存在して、
とおくことができる。
よって、
ゆえに、
コード(Emacs)
Python 3
#!/usr/bin/env python3
from sympy import pprint, gcd
import random
def mod(a, b, m):
return (a - b) % m == 0
for _ in range(10):
a = random.randrange(-100, 100)
b = random.randrange(-100, 100)
m = random.randrange(1, 20)
b += ((a % m) - (b % m))
for d in range(1, m + 1):
if m % d == 0:
break
print(f'a = {a}, b = {b}, m = {m}, d = {d}')
for t in [mod(a, b, m), mod(a, b, d)]:
pprint(t)
print()
入出力結果(Terminal, Jupyter(IPython))
$ ./sample5.py a = -98, b = -93, m = 5, d = 1 True True a = -14, b = 25, m = 13, d = 1 True True a = 13, b = -55, m = 4, d = 1 True True a = 13, b = -52, m = 1, d = 1 True True a = -12, b = 20, m = 2, d = 1 True True a = 79, b = 24, m = 5, d = 1 True True a = 79, b = -41, m = 10, d = 1 True True a = 98, b = -72, m = 10, d = 1 True True a = 8, b = 62, m = 9, d = 1 True True a = -80, b = 80, m = 10, d = 1 True True $
HTML5
<pre id="output0"></pre> <input id="a0" type="number" step="1" value="12"> ≡ <input id="b0" type="number" step="1" value="22"> (mod <input id="m0" type="number" step="1" value="10">) <br> d = <input id="d0" type="number" min="1" step="1" value="2"> <button id="run0">run</button> <button id="clear0">clear</button> <script src="sample5.js"></script>
JavaScript
let pre0 = document.querySelector('#output0'),
run0 = document.querySelector('#run0'),
clear0 = document.querySelector('#clear0'),
input_a0 = document.querySelector('#a0'),
input_b0 = document.querySelector('#b0'),
input_m0 = document.querySelector('#m0'),
input_d0 = document.querySelector('#d0'),
inputs = [input_a0, input_b0, input_m0, input_d0],
range = (n) => {
let result = [];
for (let i = 0; i < n; i += 1) {
result.push(i);
}
return result;
},
p = (text) => pre0.textContent += text + '\n',
clear = () => pre0.textContent = '',
mod = (a, b, m) => (a - b) % m === 0,
output = () => {
let a = parseInt(input_a0.value, 10),
b = parseInt(input_b0.value, 10),
m = parseInt(input_m0.value, 10),
d = parseInt(input_d0.value, 10);
if ((a - b) % m == 0) {
if (m % d == 0) {
p(mod(a, b, m));
p(mod(a, b, d));
} else {
p(`${d}は${m}の約数ではない`);
}
} else {
p(`${a}と${b}は${m}を法として合同ではない`);
}
};
run0.onclick = output;
clear0.onclick = clear;
inputs.forEach((input) => input.onchange = output);
output();
≡
(mod )
d =
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