開発環境
- macOS High Sierra - Apple
- Emacs (Text Editor)
- Python 3.7 (プログラミング言語)
Head First Python (Paul Barry (著)、O'Reilly Media)のChapter 3.(Structured Data: Working with Structured Data)、FREQUENCY COUNT MAGNETS(No. 2258)を取り組んでみる。
コード(Emacs)
Python 3
#!/usr/bin/env python3 vowels = ['a', 'e', 'i', 'o', 'u'] word = input('Provide a word to search for vowels: ') found = {} found['a'] = 0 found['e'] = 0 found['i'] = 0 found['o'] = 0 found['u'] = 0 for letter in word: if letter in vowels: found[letter] += 1 for k, v in sorted(found.items()): print(f'{k} was found {v} time(s).')
入出力結果(Terminal, Jupyter(IPython))
$ ./sample1.py Provide a word to search for vowels: Python a was found 0 time(s). e was found 0 time(s). i was found 0 time(s). o was found 1 time(s). u was found 0 time(s). $ ./sample1.py Provide a word to search for vowels: aaaaa a was found 5 time(s). e was found 0 time(s). i was found 0 time(s). o was found 0 time(s). u was found 0 time(s). $
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