学習環境
- Surface Go、タイプ カバー、ペン(端末)
- Windows 10 Pro (OS)
- Nebo(Windows アプリ)
- iPad Pro + Apple Pencil
- MyScript Nebo - MyScript(iPad アプリ(iOS))
- 参考書籍
数学読本〈1〉数・式の計算/方程式/不等式 (松坂 和夫(著)、岩波書店)の第3章(数学の威力を発揮する - 方程式)、3.3(高次方程式)、連立2次方程式の問34.を取り組んでみる。
2辺の長さ を x cm、 y cm とする。
周の長さは42 cm なので
円の直径は15 cm なので、
2次方程式の解の係数の関係により、 求める2辺の長さは、
コード(Emacs)
Python 3
#!/usr/bin/env python3
from sympy import pprint, symbols, sqrt, solve, plot
print('34.')
x, y = symbols('x, y', positive=True)
eqs = (2 * (x + y) - 42, sqrt(x ** 2 + y ** 2) - 15)
pprint(solve(eqs, dict=True))
fs = solve(eqs[0], y) + solve(eqs[1], y)
pprint(fs)
p = plot(*fs, (x, -25, 25), ylim=(-25, 25), legend=True, show=False)
colors = ['red', 'green', 'green']
for i, color in enumerate(colors):
p[i].line_color = color
p.save('sample34.png')
入出力結果(Terminal, Jupyter(IPython))
$ ./sample34.py
34.
[{x: 9, y: 12}, {x: 12, y: 9}]
⎡ ____________ ____________⎤
⎢ ╱ 2 ╱ 2 ⎥
⎣-x + 21, -╲╱ - x + 225 , ╲╱ - x + 225 ⎦
$
HTML5
<div id="graph0"></div> <pre id="output0"></pre> <label for="r0">r = </label> <input id="r0" type="number" min="0" value="1"> <label for="dx">dx = </label> <input id="dx" type="number" min="0" step="0.001" value="0.01"> <br> <label for="x1">x1 = </label> <input id="x1" type="number" value="-20"> <label for="x2">x2 = </label> <input id="x2" type="number" value="20"> <br> <label for="y1">y1 = </label> <input id="y1" type="number" value="-20"> <label for="y2">y2 = </label> <input id="y2" type="number" value="20"> <button id="draw0">draw</button> <button id="clear0">clear</button> <script type="text/javascript" src="https://cdnjs.cloudflare.com/ajax/libs/d3/4.2.6/d3.min.js" integrity="sha256-5idA201uSwHAROtCops7codXJ0vja+6wbBrZdQ6ETQc=" crossorigin="anonymous"></script> <script src="sample34.js"></script>
JavaScript
let div0 = document.querySelector('#graph0'),
pre0 = document.querySelector('#output0'),
width = 600,
height = 600,
padding = 50,
btn0 = document.querySelector('#draw0'),
btn1 = document.querySelector('#clear0'),
input_r = document.querySelector('#r0'),
input_dx = document.querySelector('#dx'),
input_x1 = document.querySelector('#x1'),
input_x2 = document.querySelector('#x2'),
input_y1 = document.querySelector('#y1'),
input_y2 = document.querySelector('#y2'),
inputs = [input_r, input_dx, input_x1, input_x2, input_y1, input_y2],
p = (x) => pre0.textContent += x + '\n';
let fns = [[x => -x + 21, 'red'],
[x => -Math.sqrt(-(x ** 2) + 225), 'green'],
[x => Math.sqrt(-(x ** 2) + 225), 'green']];
let draw = () => {
pre0.textContent = '';
let r = parseFloat(input_r.value),
dx = parseFloat(input_dx.value),
x1 = parseFloat(input_x1.value),
x2 = parseFloat(input_x2.value),
y1 = parseFloat(input_y1.value),
y2 = parseFloat(input_y2.value);
if (r === 0 || dx === 0 || x1 > x2 || y1 > y2) {
return;
}
let points = [],
x0 = 10,
y0 = 12,
lines = [[9, y1, 9, y2, 'blue'],
[12, y1, 12, y2, 'brown']];
fns
.forEach((o) => {
let [f, color] = o;
for (let x = x1; x <= x2; x += dx) {
let y = f(x);
points.push([x, y, color]);
}
});
let xscale = d3.scaleLinear()
.domain([x1, x2])
.range([padding, width - padding]);
let yscale = d3.scaleLinear()
.domain([y1, y2])
.range([height - padding, padding]);
let xaxis = d3.axisBottom().scale(xscale);
let yaxis = d3.axisLeft().scale(yscale);
div0.innerHTML = '';
let svg = d3.select('#graph0')
.append('svg')
.attr('width', width)
.attr('height', height);
svg.selectAll('line')
.data([[x1, 0, x2, 0], [0, y1, 0, y2]].concat(lines))
.enter()
.append('line')
.attr('x1', (d) => xscale(d[0]))
.attr('y1', (d) => yscale(d[1]))
.attr('x2', (d) => xscale(d[2]))
.attr('y2', (d) => yscale(d[3]))
.attr('stroke', (d) => d[4] || 'black');
svg.selectAll('circle')
.data(points)
.enter()
.append('circle')
.attr('cx', (d) => xscale(d[0]))
.attr('cy', (d) => yscale(d[1]))
.attr('r', r)
.attr('fill', (d) => d[2] || 'green');
svg.append('g')
.attr('transform', `translate(0, ${height - padding})`)
.call(xaxis);
svg.append('g')
.attr('transform', `translate(${padding}, 0)`)
.call(yaxis);
[fns].forEach((fs) => p(fs.join('\n')));
};
inputs.forEach((input) => input.onchange = draw);
btn0.onclick = draw;
btn1.onclick = () => pre0.textContent = '';
draw();
0 コメント:
コメントを投稿