開発環境
- macOS Sierra - Apple (OS)
- Emacs (Text Editor)
- JavaScript (プログラミング言語)
- Node.js, Safari(JavaScript エンジン)
- Learning JavaScript [邦訳](参考書籍)
Think Perl 6: How to Think Like a Computer Scientist (Laurent Rosenfeld(著)、Allen B. Downey(著)、Oreilly & Associates Inc)の Part 1(Starting with the basics)、Chapter 8(Case Study: Word Play)の Exercise 8-7、8-8、8-9.を JavaScript で取り組んでみる。
Exercise 8-7、8-8、8-9.
コード(Emacs)
HTML5
<pre id="output0"></pre> <input id="file0" type="file"> <br> <button id="run0">run</button> <button id="clear0">clear</button> <script src="sample7.js"></script>
JavaScript
let btn0 = document.querySelector('#run0'),
btn1 = document.querySelector('#clear0'),
pre0 = document.querySelector('#output0'),
input_file0 = document.querySelector('#file0'),
p = (x) => pre0.textContent += x + '\n',
range = (start, end, step=1) => {
let result = [];
for (let i = start; i < end; i += 1) {
result.push(i);
}
return result;
};
let isPalindrome = (word) => word === word.split('').reverse().join('');
let output = () => {
let file = input_file0.files[0],
reader = new FileReader();
reader.onload = () => {
let words = reader.result
.split('\n')
.map((word) => word.trim())
.filter((word) => word !== '');
p('7.');
p(
words.filter((word) => /(.)\1(.)\2(.)\3/.test(word))
.join('\n')
);
p('8.');
p(
range(100000, 1000000)
.filter((n) =>
isPalindrome(`${n}`.substring(2)) &&
isPalindrome(`${n + 1}`.substring(1)) &&
isPalindrome(`${n + 2}`.substring(1, 5)) &&
isPalindrome(`${n + 3}`))
.join('\n')
);
p('9.');
let age1 = 20,
age2 = 50;
range(age1, age2 + 1)
.forEach((diff) => {
let count = 0;
range(0, 100 - diff + 1)
.forEach((i) => {
let mum = i + diff;
if (`${i}` === `${mum}`.split('').reverse().join('')) {
p(`ME: ${i}, MUM: ${mum}`);
count += 1;
}
});
if (count > 0) {
p(`${count}: ${diff}`);
}
})
};
reader.readAsText(file);
};
btn0.onclick = output;
btn1.onclick = () => pre0.textContent = '';
output();
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