開発環境
- OS X Mavericks - Apple(OS)
- Emacs (CUI)、BBEdit - Bare Bones Software, Inc. (GUI) (Text Editor)
- Scheme (プログラミング言語)
- Gauche (処理系)
計算機プログラムの構造と解釈(Gerald Jay Sussman(原著)、Julie Sussman(原著)、Harold Abelson(原著)、和田 英一(翻訳)、ピアソンエデュケーション、原書: Structure and Interpretation of Computer Programs (MIT Electrical Engineering and Computer Science)(SICP))の2(データによる抽象の構築)、2.3(記号データ)、2.3.2(例: 記号微分)、問題 2.58-a.を解いてみる。
その他参考書籍
- Instructor's Manual to Accompany Structure & Interpretation of Computer Programs
- プログラミングGauche (Kahuaプロジェクト (著), 川合 史朗 (監修), オライリージャパン)
問題 2.58-a.
コード(BBEdit, Emacs)
sample.scm
#!/usr/bin/env gosh
;; -*- coding: utf-8 -*-
;; これまでに書いた手続き
(load "./procedures.scm")
(define (make-sum a1 a2)
(cond ((=number? a1 0) a2)
((=number? a2 0) a1)
((and (number? a1) (number? a2))
(+ a1 a2))
(else (list a1 '+ a2))))
(define (addend s) (car s))
(define (augend s) (caddr s))
(define (sum? x)
(and (pair? x) (eq? (cadr x) '+)))
(define (product? x)
(and (pair? x) (eq? (cadr x) '*)))
(define (multiplier p) (car p))
(define (multiplicand p) (caddr p))
(define (make-product m1 m2)
(cond ((or (=number? m1 0)
(=number? m2 0))
0)
((=number? m1 1) m2)
((=number? m2 1) m1)
((and (number? m1)
(number? m2))
(* m1 m2))
(else (list m1 '* m2))))
(define (make-exponentiation b e)
(cond ((=number? e 0) 1)
((=number? e 1) b)
(else
(list b '** e))))
(define (base exp) (car exp))
(define (exponent exp) (caddr exp))
(define (exponentiation? exp)
(and (pair? exp)
(eq? (cadr exp) '**)))
(define (deriv exp var)
(cond ((number? exp) 0)
((variable? exp)
(if (same-variable? exp
var)
1
0))
((sum? exp)
(make-sum (deriv (addend exp)
var)
(deriv (augend exp)
var)))
((product? exp)
(make-sum
(make-product (multiplier exp)
(deriv (multiplicand exp)
var))
(make-product (deriv (multiplier exp)
var)
(multiplicand exp))))
((exponentiation? exp)
(let ((n (exponent exp))
(u (base exp)))
(make-product
(make-product n
(make-exponentiation u
(make-sum n -1)))
(deriv u var))))
(else
(error "unknown expression type -- DERIV" #?=exp))))
(for-each (lambda (exp)
(print "(derive " exp " x) = "
(deriv exp 'x)))
(list '(x + 3)
'(x * y)
'((x * y) * (x + 3))
'(x + (3 * (x + (y + 2))))))
入出力結果(Terminal(gosh), REPL(Read, Eval, Print, Loop))
$ ./sample.scm (derive (x + 3) x) = 1 (derive (x * y) x) = y (derive ((x * y) * (x + 3)) x) = ((x * y) + (y * (x + 3))) (derive (x + (3 * (x + (y + 2)))) x) = 4 $
0 コメント:
コメントを投稿