開発環境
- OS X Mavericks - Apple(OS)
- Emacs (CUI)、BBEdit - Bare Bones Software, Inc. (GUI) (Text Editor)
- Scheme (プログラミング言語)
- Gauche (処理系)
計算機プログラムの構造と解釈(Gerald Jay Sussman(原著)、Julie Sussman(原著)、Harold Abelson(原著)、和田 英一(翻訳)、ピアソンエデュケーション、原書: Structure and Interpretation of Computer Programs (MIT Electrical Engineering and Computer Science)(SICP))の2(データによる抽象の構築)、2.2(階層データ構造と閉包性)、2.2.4(例: 図形言語)、フレーム、問題 2.46.を解いてみる。
その他参考書籍
- Instructor's Manual to Accompany Structure & Interpretation of Computer Programs
- プログラミングGauche (Kahuaプロジェクト (著), 川合 史朗 (監修), オライリージャパン)
問題 2.46.
コード(BBEdit, Emacs)
sample.scm
#!/usr/bin/env gosh
;; -*- coding: utf-8 -*-
;; これまでに書いた手続き
(load "./procedures.scm")
(define (make-vect x y)
(list x y))
(define (xcor-vect v)
(car v))
(define (ycor-vect v)
(car (cdr v)))
(define (add-vect v1 v2)
(let ((x1 (xcor-vect v1))
(y1 (ycor-vect v1))
(x2 (xcor-vect v2))
(y2 (ycor-vect v2)))
(make-vect (+ x1 x2)
(+ y1 y2))))
(define (sub-vect v1 v2)
(let ((x1 (xcor-vect v1))
(y1 (ycor-vect v1))
(x2 (xcor-vect v2))
(y2 (ycor-vect v2)))
(make-vect (- x1 x2)
(- y1 y2))))
(define (scale-vect s v)
(make-vect (* s
(xcor-vect v))
(* s
(ycor-vect v))))
(define v1 (make-vect 0 0))
(define v2 (make-vect 1 1))
(define v3 (make-vect 2 3))
(define v4 (make-vect 4 5))
(define s 100)
(define vectors (list v1 v2 v3 v4))
(define vectors-pairs (flatmap (lambda (v1)
(map (lambda (v2)
(cons v1 v2))
vectors))
vectors))
(for-each (lambda (vector-pair)
(let ((v1 (car vector-pair))
(v2 (cdr vector-pair)))
(print v1 " + " v2 " = " (add-vect v1 v2))))
vectors-pairs)
(for-each (lambda (vector-pair)
(let ((v1 (car vector-pair))
(v2 (cdr vector-pair)))
(print v1 " - " v2 " = " (sub-vect v1 v2))))
vectors-pairs)
(for-each (lambda (v)
(print s "・" v " = " (scale-vect s v)))
vectors)
入出力結果(Terminal(gosh), REPL(Read, Eval, Print, Loop))
$ ./sample.scm (0 0) + (0 0) = (0 0) (0 0) + (1 1) = (1 1) (0 0) + (2 3) = (2 3) (0 0) + (4 5) = (4 5) (1 1) + (0 0) = (1 1) (1 1) + (1 1) = (2 2) (1 1) + (2 3) = (3 4) (1 1) + (4 5) = (5 6) (2 3) + (0 0) = (2 3) (2 3) + (1 1) = (3 4) (2 3) + (2 3) = (4 6) (2 3) + (4 5) = (6 8) (4 5) + (0 0) = (4 5) (4 5) + (1 1) = (5 6) (4 5) + (2 3) = (6 8) (4 5) + (4 5) = (8 10) (0 0) - (0 0) = (0 0) (0 0) - (1 1) = (-1 -1) (0 0) - (2 3) = (-2 -3) (0 0) - (4 5) = (-4 -5) (1 1) - (0 0) = (1 1) (1 1) - (1 1) = (0 0) (1 1) - (2 3) = (-1 -2) (1 1) - (4 5) = (-3 -4) (2 3) - (0 0) = (2 3) (2 3) - (1 1) = (1 2) (2 3) - (2 3) = (0 0) (2 3) - (4 5) = (-2 -2) (4 5) - (0 0) = (4 5) (4 5) - (1 1) = (3 4) (4 5) - (2 3) = (2 2) (4 5) - (4 5) = (0 0) 100・(0 0) = (0 0) 100・(1 1) = (100 100) 100・(2 3) = (200 300) 100・(4 5) = (400 500) $
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