開発環境
- OS X Lion - Apple(OS)
- TextWrangler(Text Editor) (BBEditの機能制限無料版、light版)
- Script言語:Ruby
『初めてのプログラミング 第2版』(Chris Pine 著、長尾 高弘 訳、オライリー・ジャパン、2010年、ISBN978-4-87311-469-9)の10章(章全部で復習), 10.5(練習問題の続き)拡張english_numberを解いてみる。
その他参考書籍
拡張english_number
コード(TextWrangler)
#!/usr/bin/env ruby #encoding: utf-8 def english_number number return '負ではない数値を入力して下さい' if number < 0 return 'zero' if number == 0 num_string = '' ones_place = ['one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight', 'nine'] tens_place = ['ten', 'twenty', 'thirty', 'forty', 'fifty', 'sixty', 'seventy', 'eighty', 'ninety'] teenagers = ['eleven', 'twelve', 'thirteen', 'fourteen', 'fifteen', 'sixteen', 'seventeen', 'eighteen', 'nineteen'] others = [['hundred',2], ['thousand',3], ['million',6], ['billion',9], ['trillion',12]] left = number while others.length > 0 other = others.pop write = left / (10**other[1]) left -= write * (10**other[1]) if write > 0 pre = english_number write num_string += pre + ' ' + other[0] if left > 0 num_string += ' ' end end end write = left / 10 left -= write * 10 if write > 0 if ((write == 1) and (left > 0)) num_string += teenagers[left - 1] left = 0 else num_string += tens_place[write - 1] end if left > 0 num_string += '-' end end write = left left = 0 if write > 0 num_string += ones_place[write - 1] end num_string end numbers = [0,9,10,11,17,32,88,99,100,234,3211,999999,1000000000000] numbers.each do |number| puts "#{number}: #{english_number number}" end
入出力結果(Terminal)
$ ./ruby_program.rb 0: zero 9: nine 10: ten 11: eleven 17: seventeen 32: thirty-two 88: eighty-eight 99: ninety-nine 100: one hundred 234: two hundred thirty-four 3211: three thousand two hundred eleven 999999: nine hundred ninety-nine thousand nine hundred ninety-nine 1000000000000: one trillion $
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