開発環境
- OS X Lion - Apple(OS)
- TextWrangler(Text Editor) (BBEditの機能制限無料版、light版)
- Script言語:Ruby
『初めてのプログラミング 第2版』(Chris Pine 著、長尾 高弘 訳、オライリー・ジャパン、2010年、ISBN978-4-87311-469-9)の10章(章全部で復習), 10.5(練習問題の続き)拡張english_numberを解いてみる。
その他参考書籍
拡張english_number
コード(TextWrangler)
#!/usr/bin/env ruby
#encoding: utf-8
def english_number number
return '負ではない数値を入力して下さい' if number < 0
return 'zero' if number == 0
num_string = ''
ones_place = ['one', 'two', 'three',
'four', 'five', 'six',
'seven', 'eight', 'nine']
tens_place = ['ten', 'twenty', 'thirty',
'forty', 'fifty', 'sixty',
'seventy', 'eighty', 'ninety']
teenagers = ['eleven', 'twelve', 'thirteen',
'fourteen', 'fifteen', 'sixteen',
'seventeen', 'eighteen', 'nineteen']
others = [['hundred',2],
['thousand',3],
['million',6],
['billion',9],
['trillion',12]]
left = number
while others.length > 0
other = others.pop
write = left / (10**other[1])
left -= write * (10**other[1])
if write > 0
pre = english_number write
num_string += pre + ' ' + other[0]
if left > 0
num_string += ' '
end
end
end
write = left / 10
left -= write * 10
if write > 0
if ((write == 1) and (left > 0))
num_string += teenagers[left - 1]
left = 0
else
num_string += tens_place[write - 1]
end
if left > 0
num_string += '-'
end
end
write = left
left = 0
if write > 0
num_string += ones_place[write - 1]
end
num_string
end
numbers = [0,9,10,11,17,32,88,99,100,234,3211,999999,1000000000000]
numbers.each do |number|
puts "#{number}: #{english_number number}"
end
入出力結果(Terminal)
$ ./ruby_program.rb 0: zero 9: nine 10: ten 11: eleven 17: seventeen 32: thirty-two 88: eighty-eight 99: ninety-nine 100: one hundred 234: two hundred thirty-four 3211: three thousand two hundred eleven 999999: nine hundred ninety-nine thousand nine hundred ninety-nine 1000000000000: one trillion $
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