問16
(1)
sin(45°-30°)
=1/sqrt{2}*sqrt{3}/2-1/sqrt{2}*1/2
=(sqrt{3}-1)/2sqrt{2}
=(sqrt{6}-sqrt{2})/4
(2)
cos(45°-30°)
=1/sqrt{2}*sqrt{3}/2+1/sqrt{2}*1/2
=(sqrt{3}+1)/2sqrt{2}
=(sqrt{6}+sqrt{2})/4
(3)
sin(45°+60°)
=1/sqrta{2}*1/2+1/sqrt{2}*sqrt{3}/2
=(1+sqrt{3})/2sqrt{2}
=(sqrt{2}+sqrt{6})/4
(4)
cos(45°+60°)
=1/sqrt{2}*1/2-1/sqrt{2}*sqrt{3}/2
=(1-sqrt{3})/2sqrt{2}
=(sqrt{2}-sqrt{6})/4
(5)
sqrt{3}/2
(6)
-1/2
(7)
sin15°
=(sqrt{6}-sqrt{2})/4
(8)
-cos15°
=-(sqrt{6}+sqrt{2})/4
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